Optimal. Leaf size=208 \[ -\frac{\sin (e+f x) \cos (e+f x) \text{Hypergeometric2F1}\left (\frac{1}{2},\frac{1}{2} (1-n p),\frac{1}{2} (3-n p),\cos ^2(e+f x)\right ) \left (c (d \sec (e+f x))^p\right )^n}{a f \sqrt{\sin ^2(e+f x)}}+\frac{(1-n p) \sin (e+f x) \cos ^2(e+f x) \text{Hypergeometric2F1}\left (\frac{1}{2},\frac{1}{2} (2-n p),\frac{1}{2} (4-n p),\cos ^2(e+f x)\right ) \left (c (d \sec (e+f x))^p\right )^n}{a f (2-n p) \sqrt{\sin ^2(e+f x)}}+\frac{\sin (e+f x) \left (c (d \sec (e+f x))^p\right )^n}{f (a \sec (e+f x)+a)} \]
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Rubi [A] time = 0.271023, antiderivative size = 208, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 5, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.185, Rules used = {3948, 3820, 3787, 3772, 2643} \[ -\frac{\sin (e+f x) \cos (e+f x) \, _2F_1\left (\frac{1}{2},\frac{1}{2} (1-n p);\frac{1}{2} (3-n p);\cos ^2(e+f x)\right ) \left (c (d \sec (e+f x))^p\right )^n}{a f \sqrt{\sin ^2(e+f x)}}+\frac{(1-n p) \sin (e+f x) \cos ^2(e+f x) \, _2F_1\left (\frac{1}{2},\frac{1}{2} (2-n p);\frac{1}{2} (4-n p);\cos ^2(e+f x)\right ) \left (c (d \sec (e+f x))^p\right )^n}{a f (2-n p) \sqrt{\sin ^2(e+f x)}}+\frac{\sin (e+f x) \left (c (d \sec (e+f x))^p\right )^n}{f (a \sec (e+f x)+a)} \]
Antiderivative was successfully verified.
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Rule 3948
Rule 3820
Rule 3787
Rule 3772
Rule 2643
Rubi steps
\begin{align*} \int \frac{\left (c (d \sec (e+f x))^p\right )^n}{a+a \sec (e+f x)} \, dx &=\left ((d \sec (e+f x))^{-n p} \left (c (d \sec (e+f x))^p\right )^n\right ) \int \frac{(d \sec (e+f x))^{n p}}{a+a \sec (e+f x)} \, dx\\ &=\frac{\left (c (d \sec (e+f x))^p\right )^n \sin (e+f x)}{f (a+a \sec (e+f x))}-\frac{\left (d (1-n p) (d \sec (e+f x))^{-n p} \left (c (d \sec (e+f x))^p\right )^n\right ) \int (d \sec (e+f x))^{-1+n p} (a-a \sec (e+f x)) \, dx}{a^2}\\ &=\frac{\left (c (d \sec (e+f x))^p\right )^n \sin (e+f x)}{f (a+a \sec (e+f x))}+\frac{\left ((1-n p) (d \sec (e+f x))^{-n p} \left (c (d \sec (e+f x))^p\right )^n\right ) \int (d \sec (e+f x))^{n p} \, dx}{a}-\frac{\left (d (1-n p) (d \sec (e+f x))^{-n p} \left (c (d \sec (e+f x))^p\right )^n\right ) \int (d \sec (e+f x))^{-1+n p} \, dx}{a}\\ &=\frac{\left (c (d \sec (e+f x))^p\right )^n \sin (e+f x)}{f (a+a \sec (e+f x))}+\frac{\left ((1-n p) \left (\frac{\cos (e+f x)}{d}\right )^{n p} \left (c (d \sec (e+f x))^p\right )^n\right ) \int \left (\frac{\cos (e+f x)}{d}\right )^{-n p} \, dx}{a}-\frac{\left (d (1-n p) \left (\frac{\cos (e+f x)}{d}\right )^{n p} \left (c (d \sec (e+f x))^p\right )^n\right ) \int \left (\frac{\cos (e+f x)}{d}\right )^{1-n p} \, dx}{a}\\ &=\frac{\left (c (d \sec (e+f x))^p\right )^n \sin (e+f x)}{f (a+a \sec (e+f x))}-\frac{\cos (e+f x) \, _2F_1\left (\frac{1}{2},\frac{1}{2} (1-n p);\frac{1}{2} (3-n p);\cos ^2(e+f x)\right ) \left (c (d \sec (e+f x))^p\right )^n \sin (e+f x)}{a f \sqrt{\sin ^2(e+f x)}}+\frac{(1-n p) \cos ^2(e+f x) \, _2F_1\left (\frac{1}{2},\frac{1}{2} (2-n p);\frac{1}{2} (4-n p);\cos ^2(e+f x)\right ) \left (c (d \sec (e+f x))^p\right )^n \sin (e+f x)}{a f (2-n p) \sqrt{\sin ^2(e+f x)}}\\ \end{align*}
Mathematica [F] time = 1.20468, size = 0, normalized size = 0. \[ \int \frac{\left (c (d \sec (e+f x))^p\right )^n}{a+a \sec (e+f x)} \, dx \]
Verification is Not applicable to the result.
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Maple [F] time = 0.15, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( c \left ( d\sec \left ( fx+e \right ) \right ) ^{p} \right ) ^{n}}{a+a\sec \left ( fx+e \right ) }}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (\left (d \sec \left (f x + e\right )\right )^{p} c\right )^{n}}{a \sec \left (f x + e\right ) + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\left (\left (d \sec \left (f x + e\right )\right )^{p} c\right )^{n}}{a \sec \left (f x + e\right ) + a}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{\left (c \left (d \sec{\left (e + f x \right )}\right )^{p}\right )^{n}}{\sec{\left (e + f x \right )} + 1}\, dx}{a} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (\left (d \sec \left (f x + e\right )\right )^{p} c\right )^{n}}{a \sec \left (f x + e\right ) + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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